Question

Which of the following are the roots of `3x^2+2x-1=0?` 

`1/3`

Answer 1

On subtracting `x= 1/3` in the given equation , We get : 

L.H.S = `3x^2x-1` 

`=3xx(1/3)^2+2xx1/3-1` 

=`3xx1/9+2/3-1` 

`=(1+2-3)/3` 

`=0/3` 

=0 

R.H.S 

Thus, `(1/3)`is a root of `(3x^2+2x-1=0)`