English

Which expression gives the axial component \(dB_x\) from a loop element \(dl\)?

Advertisements
Advertisements

Question

Which expression gives the axial component \(dB_x\) from a loop element \(dl\)?

Options

  • \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{x}{(x^2+R^2)^{3/2}}\)

  • \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{1}{(x^2+R^2)^{1/2}}\)

  • \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{(x^2+R^2)^{3/2}}\)

  • \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{x^2+R^2}\)

MCQ
Advertisements

Solution

The axial component is obtained by using the loop geometry with the Biot–Savart contribution. It is \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{(x^2+R^2)^{3/2}}\).

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×