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प्रश्न
Which expression gives the axial component \(dB_x\) from a loop element \(dl\)?
पर्याय
\(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{x}{(x^2+R^2)^{3/2}}\)
\(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{1}{(x^2+R^2)^{1/2}}\)
\(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{(x^2+R^2)^{3/2}}\)
\(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{x^2+R^2}\)
MCQ
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उत्तर
The axial component is obtained by using the loop geometry with the Biot–Savart contribution. It is \(dB_x=\frac{\mu_0 I dl}{4\pi}\cdot\frac{R}{(x^2+R^2)^{3/2}}\).
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