Question

Which equation follows from the right-angle phasor triangle for the peak applied voltage?

Options

• \[v_m^2=V_{Rm}^2+V_{Cm}^2+V_{Lm}^2\]

• \[v_m^2=V_{Rm}^2+(V_{Cm}-V_{Lm})^2\]

• \[v_m^2=(V_{Rm}+V_{Cm}-V_{Lm})^2\]

• \[v_m^2=V_{Rm}^2+(V_{Cm}+V_{Lm})^2\]

Answer 1

The right-angle phasor triangle gives \[v_m^2=V_{Rm}^2+(V_{Cm}-V_{Lm})^2\]. The capacitor and inductor voltage contributions enter as a difference.