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प्रश्न
Which equation follows from the right-angle phasor triangle for the peak applied voltage?
पर्याय
\[v_m^2=V_{Rm}^2+V_{Cm}^2+V_{Lm}^2\]
\[v_m^2=V_{Rm}^2+(V_{Cm}-V_{Lm})^2\]
\[v_m^2=(V_{Rm}+V_{Cm}-V_{Lm})^2\]
\[v_m^2=V_{Rm}^2+(V_{Cm}+V_{Lm})^2\]
MCQ
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उत्तर
The right-angle phasor triangle gives \[v_m^2=V_{Rm}^2+(V_{Cm}-V_{Lm})^2\]. The capacitor and inductor voltage contributions enter as a difference.
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