Question

When every turn of a coil of \[N\] turns contributes equally, what is its magnetic flux linkage?

Options

• \[\Phi=NBA\sin\theta\]

• \[\Phi=NBA\cos\theta\]

• \[\Phi=BA\cos\theta\]

• \[\Phi=\frac{BA\cos\theta}{N}\]

Answer 1

For equal contributions from all turns, the coil's magnetic flux linkage is \[\Phi=NBA\cos\theta\]. The factor \[N\] accounts for the number of turns.