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प्रश्न
When every turn of a coil of \[N\] turns contributes equally, what is its magnetic flux linkage?
पर्याय
\[\Phi=NBA\sin\theta\]
\[\Phi=NBA\cos\theta\]
\[\Phi=BA\cos\theta\]
\[\Phi=\frac{BA\cos\theta}{N}\]
MCQ
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उत्तर
For equal contributions from all turns, the coil's magnetic flux linkage is \[\Phi=NBA\cos\theta\]. The factor \[N\] accounts for the number of turns.
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