Question

When an electron (\[q = e = 1.6 \times 10^{-19}\ \text{C}\]) is accelerated through a potential difference of 1 Volt, the energy gained is:

Options

• \[1\ \text{J}\]

• \[1.6 \times 10^{-16}\ \text{J} = 1\ \text{keV}\]

• \[1.6 \times 10^{-19}\ \text{J} = 1\ \text{eV}\]

• \[1.6 \times 10^{-13}\ \text{J} = 1\ \text{MeV}\]

Answer 1

Using \[U = qV\]: \[U = (1.6 \times 10^{-19}\ \text{C})(1\ \text{V}) = 1.6 \times 10^{-19}\ \text{J}\]. This energy defines 1 electron volt (1 eV).