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प्रश्न
When an electron (\[q = e = 1.6 \times 10^{-19}\ \text{C}\]) is accelerated through a potential difference of 1 Volt, the energy gained is:
पर्याय
\[1\ \text{J}\]
\[1.6 \times 10^{-16}\ \text{J} = 1\ \text{keV}\]
\[1.6 \times 10^{-19}\ \text{J} = 1\ \text{eV}\]
\[1.6 \times 10^{-13}\ \text{J} = 1\ \text{MeV}\]
MCQ
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उत्तर
Using \[U = qV\]: \[U = (1.6 \times 10^{-19}\ \text{C})(1\ \text{V}) = 1.6 \times 10^{-19}\ \text{J}\]. This energy defines 1 electron volt (1 eV).
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