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Question
When a plate of magnetic material of size 10 cm × 0.5 cm × 0.2 cm (length, breadth, and thickness respectively ) is located in the magnetizing field of 0.5 × 104 Am-1 then a magnetic moment of 5 Am2 is induced in it. Find out magnetic induction in the plate.
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Solution
Given:
l = 10 cm = 10-1 m,
b = 0.5 cm = 5 × 10-3 m,
h = 0.2 cm = 2 × 10-3 m,
H = 0.5 × 104 Am-1 = 5 × 103 Am-1
μ0 = 4π × 10-7 TmA-1
mnet = 5 Am2
To find: Magnetic induction in the plate (B)
Formulae:
- M = `"m"_"net"/"V"`
- B = μ0 = (M + H)
Calculation:
From formula (i),
M = `5/(10^-1 xx 5 xx 10^-3 xx 2 xx 10^-3)`
= 5 × 106 Am-1
From formula (ii),
B = `4 xx 3.142 xx 10^-7 [5 xx 10^6 + 5 xx 10^3]`
= `12.568 xx 10^-7 xx 5 xx 10^3 [10^3 + 1]`
= `6.284 xx 10^-3 xx 1001`
= `6.29 xx 10^3 xx 10^-3`
= 6.29 T
Magnetic induction in the plate is 6.29 T.
