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Karnataka Board PUCPUC Science 2nd PUC Class 12

When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solut

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Question

When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solution with sulphuric acid, compound (C) can be crystallised from the solution. When compound (C) is treated with KCl, orange crystals of compound (D) crystallise out. Identify A to D and also explain the reactions.

Long Answer
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Solution

The compounds A, B, C and D are given as under:

A = \[\ce{FeCr2O4}\]

B = \[\ce{Na2CrO4}\]

C = \[\ce{Na2Cr2O7.2H2O}\]

D = \[\ce{K2Cr2O7}\]

The reactions are explained as under:

\[\ce{\underset{(A)}{4FeCr2O4} + 8NaCO3 + 7O2 -> \underset{(B)}{8Na2CrO4} + 2Fe2O3 + 8CO2}\]

\[\ce{2NaCrO4 + 2H^+ -> Na2CrO7 + 2Na^+ + H2O}\]

\[\ce{\underset{(C)}{Na2CrO7} + 2KCl -> \underset{(D)}{K2Cr2O7} + 2NaCl}\]

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Chapter 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [Page 114]

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NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 65 | Page 114

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