Question

What volume of CO₂ under S.T.P. conditions will be obtained by burning 1 kg of carbon in an excess of oxygen?

Answer 1

\[\ce{C + O2 -> CO2}\]

12 g of Carbon → 22.4 L of CO₂ at S.T.P.

Mass of carbon = 1 kg = 1000 g

Volume of gas obtained = `(22.4  L)/(12  g) xx 1000  g`

= 1866.67 L (or dm³)

1866.67 L of gas is obtained at S.T.P.