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प्रश्न
What volume of CO2 under S.T.P. conditions will be obtained by burning 1 kg of carbon in an excess of oxygen?
संख्यात्मक
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उत्तर
\[\ce{C + O2 -> CO2}\]
12 g of Carbon → 22.4 L of CO2 at S.T.P.
Mass of carbon = 1 kg = 1000 g
Volume of gas obtained = `(22.4 L)/(12 g) xx 1000 g`
= 1866.67 L (or dm3)
1866.67 L of gas is obtained at S.T.P.
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