Question

What volume of ammonia is required to produce 130 cm³ of steam?

\[\ce{4NH3 + 5O2 -> 4NO + 6H2O}\]

Answer 1

Reaction: \[\ce{4NH3 + 5O2 -> 4NO + 6H2O}\]

According to Gay-Lussac's Law:

4 volumes of NH₃ produce → 6 volumes of H₂O (steam)

Calculation:

Volume of NH₃ required = `4/6` × Volume of steam

= `2/3 xx 130  cm^3`

= 86.67 cm³

86.67 cm³ of ammonia gas is required.