Question

A sample of ammonium nitrate upon heating yields 7.58 dm³ of steam.

\[\ce{NH4NO3 -> N2O + 2H2O}\]

What volume of N₂O is released?

Answer 1

Reaction: \[\ce{NH4NO3 ->[\Delta] N2O + 2H2O}\] (steam)

According to Gay-Lussac's Law:

1 volumes of N₂O is released along with → 2 volumes of H₂O (steam)

Calculation:

Volume of N₂O = `1/2` × Volume of steam

= `1/2 xx 7.58  dm^3`

= 3.79 dm³

3.79 dm³ of N₂O gas is released.