Advertisements
Advertisements
Question
What must be added to x4 + 2x3 − 2x2 + x − 1 , so that the resulting polynomial is exactly divisible by x2 + 2x − 3?
Advertisements
Solution

Thus, (x - 2) should be added to (\[x^4 + 2 x^3 - 2 x^2 + x - 1\] ) to make the resulting polynomial exactly divisible by \[(x^2 + 2x - 3)\]
RELATED QUESTIONS
Which of the following expressions are not polynomials?
Which of the following expressions are not polynomials?
Divide −21abc2 by 7abc.
Divide \[y^4 - 3 y^3 + \frac{1}{2} y^2 by 3y\]
Divide\[\sqrt{3} a^4 + 2\sqrt{3} a^3 + 3 a^2 - 6a\ \text{by}\ 3a\]
Divide 2y5 + 10y4 + 6y3 + y2 + 5y + 3 by 2y3 + 1.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 6y5 − 28y3 + 3y2 + 30y − 9 | 2y2 − 6 |
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 34x − 22x3 − 12x4 − 10x2 − 75 | 3x + 7 |
Find whether the first polynomial is a factor of the second.
4 − z, 3z2 − 13z + 4
Divide 27y3 by 3y
