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प्रश्न
What must be added to x4 + 2x3 − 2x2 + x − 1 , so that the resulting polynomial is exactly divisible by x2 + 2x − 3?
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उत्तर
Thus, (x - 2) should be added to (\[x^4 + 2 x^3 - 2 x^2 + x - 1\] ) to make the resulting polynomial exactly divisible by \[(x^2 + 2x - 3)\]
संबंधित प्रश्न
Divide the given polynomial by the given monomial.
(x3 + 2x2 + 3x) ÷ 2x
Divide\[\sqrt{3} a^4 + 2\sqrt{3} a^3 + 3 a^2 - 6a\ \text{by}\ 3a\]
Divide 5x3 − 15x2 + 25x by 5x.
Divide 4z3 + 6z2 − z by −\[\frac{1}{2}\]
Divide 3x3y2 + 2x2y + 15xy by 3xy.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 15y4 − 16y3 + 9y2 −\[\frac{10}{3}\] y+6 | 3y − 2 |
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 6y5 + 4y4 + 4y3 + 7y2 + 27y + 6 | 2y3 + 1 |
Divide `15 y^4 + 16 y^3 + 10-3 y - 9y^2 - 6` by 3y − 2. Write down the coefficients of the terms in the quotient.
Divide:
ax2 − ay2 by ax + ay
Divide: (32y2 – 8yz) by 2y
