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What is the value of \[\frac{d^{2}y}{dx^{2}}+y\] for \[y=a\sin(x+b)\]?

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Question

What is the value of \[\frac{d^{2}y}{dx^{2}}+y\] for \[y=a\sin(x+b)\]?

Options

  • \[a\sin(x+b)+a\sin(x+b)=2a\sin(x+b)\]

  • \[a\cos(x+b)+a\sin(x+b)=0\]

  • \[-a\sin(x+b)+a\sin(x+b)=0\]

  • \[-a\cos(x+b)+a\sin(x+b)=0\]

MCQ
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Solution

For this function, \[\frac{d^{2}y}{dx^{2}}=-a\sin(x+b)\] and \[y=a\sin(x+b)\]. Their sum is zero, so the differential equation is satisfied.

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