Question

What is the total flux linkage of secondary solenoid \[S_2\] ?

Options

• \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2I_1\]

• \[N_2\phi_{21}=\frac{\mu_0n_1n_2\pi r_2^2I_1}{l}\]

• \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_1^2I_1\]

• \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2\]

Answer 1

Multiply the flux through each turn by \[N_2=n_2l\] . This gives \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2I_1\] .