हिंदी

What is the total flux linkage of secondary solenoid \[S_2\] ?

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प्रश्न

What is the total flux linkage of secondary solenoid \[S_2\] ?

विकल्प

  • \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2I_1\]

  • \[N_2\phi_{21}=\frac{\mu_0n_1n_2\pi r_2^2I_1}{l}\]

  • \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_1^2I_1\]

  • \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2\]

MCQ
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उत्तर

Multiply the flux through each turn by \[N_2=n_2l\] . This gives \[N_2\phi_{21}=\mu_0n_1n_2l\pi r_2^2I_1\] .

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