Question

What is the resonance frequency corresponding to \[\omega_0=222.1\,\mathrm{rad/s}\]?

Options

• \[\nu_r=50\,\mathrm{Hz}\]

• \[\nu_r=66.7\,\mathrm{Hz}\]

• \[\nu_r=35.4\,\mathrm{Hz}\]

• \[\nu_r=222.1\,\mathrm{Hz}\]

Answer 1

Resonance frequency is \[\nu_r=\frac{\omega_0}{2\pi}\]. Dividing \[222.1\,\mathrm{rad/s}\] by \[2\pi\] gives approximately \[35.4\,\mathrm{Hz}\].