हिंदी

What is the resonance frequency corresponding to \[\omega_0=222.1\,\mathrm{rad/s}\]?

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प्रश्न

What is the resonance frequency corresponding to \[\omega_0=222.1\,\mathrm{rad/s}\]?

विकल्प

  • \[\nu_r=50\,\mathrm{Hz}\]

  • \[\nu_r=66.7\,\mathrm{Hz}\]

  • \[\nu_r=35.4\,\mathrm{Hz}\]

  • \[\nu_r=222.1\,\mathrm{Hz}\]

MCQ
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उत्तर

Resonance frequency is \[\nu_r=\frac{\omega_0}{2\pi}\]. Dividing \[222.1\,\mathrm{rad/s}\] by \[2\pi\] gives approximately \[35.4\,\mathrm{Hz}\].

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