Advertisements
Advertisements
Question
What is the remainder when x2018 + 2018 is divided by x – 1
Advertisements
Solution
p(x) = x2018 + 2018
When it is divided by x – 1,
p(1) = 12018 + 2018
= 1 + 2018
= 2019
The remainder is 2019.
APPEARS IN
RELATED QUESTIONS
Use the Remainder Theorem to factorise the following expression:]
`2x^3 + x^2 - 13x + 6`
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Using the Remainder Theorem, factorise the following completely:
x3 + x2 – 4x – 4
When x3 + 3x2 – mx + 4 is divided by x – 2, the remainder is m + 3. Find the value of m.
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
If ( x31 + 31) is divided by (x + 1) then find the remainder.
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
