Advertisements
Advertisements
Question
Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3)
Advertisements
Solution
p(x) = 3x3 – 4x2 + 7x – 5
When it is divided by x + 3,
p(–3) = 3(–3)3 – 4(–3)2 + 7(–3) – 5
= 3(–27) – 4(9) – 21 – 5
= – 81 – 36 – 21 – 5
= –143
The remainder is –143.
APPEARS IN
RELATED QUESTIONS
What must be subtracted from 16x3 – 8x2 + 4x + 7 so that the resulting expression has 2x + 1 as a factor?
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 19x + 6
Find the value of a, if the division of ax3 + 9x2 + 4x – 10 by x + 3 leaves a remainder 5.
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
The polynomials 2x3 – 7x2 + ax – 6 and x3 – 8x2 + (2a + 1)x – 16 leaves the same remainder when divided by x – 2. Find the value of ‘a’.
Find ‘a‘ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leave the same remainder when divided by x + 3.
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
What number must be subtracted from 2x2 – 5x so that the resulting polynomial leaves the remainder 2, when divided by 2x + 1 ?
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x + 3
