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Question
What is the ratio of inductive and capacitive reactance in an ac circuit?
Options
ω2LC
LC2
`(LC)/omega^2`
`omega^2L`
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Solution
ω2LC
Explanation:
Inductive reactance, XL = ωL
Capacitive reactance, `X_C = 1/(omegaC)`
Therefore, `X_L/X_C = (omegaL)/((1"/"omegaC))`
= `omega^2LC`
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