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Question
What is the percentage dissociation of 0.1 M solution of acetic acid? \[\ce{[Ka(CH3COOH) = 10^{-5}]}\]
Options
0.01%
1%
10%
100%
MCQ
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Solution
1%
Explanation:
Ka = α2c
∴ α = `sqrt(K_a)/c`
= `sqrt(10^-5)/0.1`
= `sqrt(10^-4)`
= 10−2
Percent dissociation = α × 100
= 10−2 × 100
= 1%
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