Question

What is the percentage dissociation of 0.1 M solution of acetic acid? \[\ce{[Ka(CH3COOH) = 10^{-5}]}\]

विकल्प

• 0.01%

• 1%

• 10%

• 100%

Answer 1

1%

Explanation:

Ka = α²c

∴ α = `sqrt(K_a)/c`

= `sqrt(10^-5)/0.1`

= `sqrt(10^-4)`

= 10⁻²

Percent dissociation = α × 100

= 10⁻² × 100

= 1%