Question

What is the nature of roots of the quadratic equation 4x² – 12x – 9 = 0?

Answer 1

The given quadric equation is 4x² − 12x − 9 = 0

Here, a = 4, b = -12 and c = -9

As we know that `D = b^2 - 4ac`

Putting the value of

 `a = 4, b = -12 and c = -9`

`(-12)^2 - 4 xx 4 xx -9`

= 144 + 144

= 288

Since, D ≥ 0 

Therefore, roots of the given equation are real and distinct.