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Question
What is the induced EMF in the secondary coil?
Options
\[e_s=-N_p\frac{d\Phi}{dt}\]
\[e_s=-N_s\frac{dt}{d\Phi}\]
\[e_s=N_s\Phi\]
\[e_s=-N_s\frac{d\Phi}{dt}\]
MCQ
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Solution
Faraday's Law gives the secondary EMF as \[e_s=-N_s\frac{d\Phi}{dt}\]. It uses the number of secondary turns and the same changing flux.
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