Question

What is the induced EMF in the secondary coil?

पर्याय

• \[e_s=-N_p\frac{d\Phi}{dt}\]

• \[e_s=-N_s\frac{dt}{d\Phi}\]

• \[e_s=N_s\Phi\]

• \[e_s=-N_s\frac{d\Phi}{dt}\]

Answer 1

Faraday's Law gives the secondary EMF as \[e_s=-N_s\frac{d\Phi}{dt}\]. It uses the number of secondary turns and the same changing flux.