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Question
If the potential difference across the ends of a conductor is 220 V and the resistance of the conductor is 44 Ω (ohm), then the current flowing through is _________.
- 0.2 A
- 0.5 A
- 2 A
- 5 A
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Solution
(d) 5 A
V = IR
∴ 220 V = I x 44 Ω
Or, `"I"=(220"V")/(44Omega)=5"A"`
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