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Karnataka Board PUCPUC Science Class 11

We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say 10 cm.

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Question

We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say 10 cm. We can use a bimetallic strip made of brass and iron each of different length whose length (both components) would change in such a way that difference between their lengths remain constant. If αiron = 1.2 × 10−5/K and αbrass = 1.8 × 10−5/K, what should we take as length of each strip?

Long Answer
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Solution

According to the problem, L1 – Lb = 10 cm where,

L1 = length of iron scale

Lb = Length of brass scale

This condition is possible if the change in length of both rods is remain the same at all temperatures.

Change in length of iron rod,

`ΔL = α_IL_IΔT`

Change in length of brass rod,

`ΔL = α_BL_BΔT`

As the change will equal in both the rods, so

`α_IL_IΔT = α_BL_BΔT`

⇒ `α_IL_I = α_BL_B`

⇒ `L_I/L_B = α_B/α_I`

Here, `α_B = 1.8 xx 10^-5 K^-1, α_I = 1.2 xx 10^-5 K^-1`

∴ `L_I/L_B = (1.8 xx 10^-5)/(1.2 xx 10^-5) = 3/2`

`L_I = 3/2 L_B`

As, `L_I - L_B` = 10 cm

∴ `3/2 L_B - L_B` = 10

⇒ `1/2 L_B` = 10

⇒ LB = 20 cm.

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Chapter 11: Thermal Properties of Matter - Exercises [Page 82]

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NCERT Exemplar Physics Exemplar [English] Class 11
Chapter 11 Thermal Properties of Matter
Exercises | Q 11.22 | Page 82

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