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Question
We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor for these solutions will be in the order ______.
Options
iA < iB < iC
iA > iB > iC
iA = iB = iC
iA < iB > iC
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Solution
iA = iB = iC
Explanation:
The value of van’t Hoff’s factor will be iA = iB = iC due to complete dissociation of strong electrolyte (NaCl) in dilute solutions. On complete dissociation value of i for NaCl is 2.
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