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Karnataka Board PUCPUC Science 2nd PUC Class 12

We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor for these solutions will - Chemistry

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Question

We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor for these solutions will be in the order ______.

Options

  • iA < iB < iC

  • iA > iB > iC

  • iA = iB = iC

  • iA < iB > iC

MCQ
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Solution

iA = iB = iC

Explanation:

The value of van’t Hoff’s factor will be iA = iB = iC due to complete dissociation of strong electrolyte (NaCl) in dilute solutions. On complete dissociation value of i for NaCl is 2.

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Chapter 2: Solutions - Exercises [Page 20]

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NCERT Exemplar Chemistry [English] Class 12
Chapter 2 Solutions
Exercises | Q I. 20. | Page 20

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