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Maharashtra State BoardSSC (English Medium) 10th Standard

Vivek is older than Kishor by 5 years. The sum of the reciprocals of their ages is 16 Find their present ages. - Algebra

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Question

Vivek is older than Kishor by 5 years. The sum of the reciprocals of their ages is \[\frac{1}{6}\] Find their present ages. 

Sum
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Solution

Let the present age of Kishor be x years.

Vivek is older than Kishor by 5 years.

So, Vivek's age will be x + 5.

The sum of the reciprocals of their ages is  \[\frac{1}{6}\] 

\[\frac{1}{x} + \frac{1}{x + 5} = \frac{1}{6}\]

\[ \Rightarrow \frac{x + 5 + x}{x\left( x + 5 \right)} = \frac{1}{6}\]

\[ \Rightarrow \frac{5 + 2x}{x^2 + 5x} = \frac{1}{6}\]

⇒ 6 (5 + 2x) = 1(x2 + 5x)

⇒ 30 + 12x = x2 + 5x

⇒ x2 + 5x - 12x - 30 = 0 

⇒ x2 - 7x - 30 = 0

⇒ x2 - 10x + 3x - 30 = 0

⇒ (x - 10) + 3(x - 10) = 0

⇒ (x + 3) (x - 10) = 0

⇒ x = -3 or x = 10

But age cannot be negative so, age of Kishore is 10 years and that of Vivek is 10 + 5 = 15 years. 

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Chapter 2: Quadratic Equations - Practice Set 2.6 [Page 52]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Practice Set 2.6 | Q 4 | Page 52
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