Advertisements
Advertisements
Question
Verify that A(2, 7) is not a point on the line x + 2y + 2 = 0.
Advertisements
Solution
Given equation is x + 2y + 2 = 0.
Substituting x = 2 and y = 7 in L.H.S. of given equation, we get
L.H.S. = x + 2y + 2
= 2 + 2(7) + 2
= 2 + 14 + 2
= 18
≠ R.H.S.
∴ Point A does not lie on the given line.
APPEARS IN
RELATED QUESTIONS
Find the equation of the line passing through the points A(2, 0) and B(3, 4).
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equation of the median AD.
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of the line passing through the mid points of sides AB and BC.
Find the x and y-intercepts of the following line: `(3x)/2 + (2y)/3` = 1
Find the x and y-intercepts of the following line: 2x – 3y + 12 = 0
Find the equations of a line containing the point A(3, 4) and making equal intercepts on the co-ordinate axes.
Find the slope, x-intercept, y-intercept of the following line : x + 2y = 0
Write the following equation in ax + by + c = 0 form: y = 2x – 4
Write the following equation in ax + by + c = 0 form: y = 4
Write the following equation in ax + by + c = 0 form: `x/3 = y/2`
Find the equation of the line whose x-intercept is 3 and which is perpendicular to the line 3x – y + 23 = 0.
Find the X-intercept of the line x + 2y – 1 = 0
Find the equation of the line: containing the point (2, 1) and having slope 13.
Find the equation of the line: through the origin which bisects the portion of the line 3x + 2y = 2 intercepted between the co-ordinate axes.
Find the equation of the line: having an inclination 60° and making intercept 4 on the Y-axis.
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of Perpendicular bisectors of sides
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of altitudes of ΔABC
