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Question
Using the common factor method, find the H.C.F. of 24, 36, 45 and 60
Sum
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Solution
F24 = 1, 2, 3, 4, 6, 8, 12, 24
F36 = 1, 2, 3, 4, 6, 12, 18, 36
F45 = 1, 3, 5, 9, 15, 45
F60 = 1, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Common factor between 24, 36, 45 and 60 = 1, 3
H.C.F. of 24, 36, 45 and 60 = 3
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