Question

Using the common factor method, find the H.C.F. of 24, 36, 45 and 60

Answer 1

F₂₄ = 1, 2, 3, 4, 6, 8, 12, 24
F₃₆ = 1, 2, 3, 4, 6, 12, 18, 36
F₄₅ = 1, 3, 5, 9, 15, 45
F₆₀ = 1, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Common factor between 24, 36, 45 and 60 = 1, 3
H.C.F. of 24, 36, 45 and 60 = 3