Question

Using only 2, 5, 10, 25 and 50 paise coins, what will be the minimum no. of coins required to pay exactly 78 paise, 69 paise and ₹ 1.01 to three different persons?

Options

• 19

• 20

• 17

• 18

Answer 1

19

Explanation:

Since we want to minimise the no. of coins, hence, maximum coins of higher denomination must be used.

78 = 50 + 10 + 10 + 2 + 2 + 2 + 2 = 7 coins

69 = 50 + 10 + 5 + 2 + 2 = 5 coins

1.01 = 50 + 25 + 10 + 10 + 2 + 2 + 2 = 7

Hence, 7 + 5 + 7 = 19 coins