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प्रश्न
Using only 2, 5, 10, 25 and 50 paise coins, what will be the minimum no. of coins required to pay exactly 78 paise, 69 paise and ₹ 1.01 to three different persons?
पर्याय
19
20
17
18
MCQ
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उत्तर
19
Explanation:
Since we want to minimise the no. of coins, hence, maximum coins of higher denomination must be used.
78 = 50 + 10 + 10 + 2 + 2 + 2 + 2 = 7 coins
69 = 50 + 10 + 5 + 2 + 2 = 5 coins
1.01 = 50 + 25 + 10 + 10 + 2 + 2 + 2 = 7
Hence, 7 + 5 + 7 = 19 coins
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Ratio and Proportion (Entrance Exam)
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