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Question
Using the method of successive subtraction examine whether or not the following numbers is perfect cube 1331 .
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Solution
We have:
1331
1
1330
7
1323
19
1304
37
1267
61
1206
91
1115
127
988
169
819
217
602
271
331
331
0
∵ The subtraction is performed 11 times.
∴ \[\sqrt[3]{1331} = 11\]
Thus, 1331 is a perfect cube.
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