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Using prime factorisation, find the cube roots of 512

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Question

Using prime factorisation, find the cube roots of 512

Sum
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Solution

First we have to find out the factors by using prime factorisation method.

2 512
2 256
2 128
2 64
2 32
2 16
2 8
2 4
2 2
  1

So, prime factors of 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2

Now, grouping the prime factors = (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2)

Then, cube root of `512 = root(3)(512)`

= `root(3)((2 xx 2 xx 2) xx (2 xx 2 xx 2) xx (2 xx 2 xx 2))`

= `root(3)(2^3 xx 2^3 xx 2^3)`

= 2 × 2 × 2

= 8

∴ The cube root of 512 is 8.

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Chapter 3: Square-Square Root and Cube-Cube Root - Exercise [Page 94]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 3 Square-Square Root and Cube-Cube Root
Exercise | Q 97. (a) | Page 94

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