Question

Use the data given in below find out which of the following is the strongest oxidising agent.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V

`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V

Options

• Cl^– 

• Mn²⁺ 

• `"MNO"_4^-`

• Cr³⁺ 

Answer 1

`"MNO"_4^-`

Explanation:

The higher the positive value of standard reduction potential of metal ion, the higher will be its oxidizing capacity.

Since, `"E"_("MnO"_4^-//"Mn"^(2+))^⊖` has value equal to 1.51 V hence it is the strongest oxidizing agent.