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प्रश्न
Use the data given in below find out which of the following is the strongest oxidising agent.
`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V
`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V
पर्याय
Cl–
Mn2+
`"MNO"_4^-`
Cr3+
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उत्तर
`"MNO"_4^-`
Explanation:
The higher the positive value of standard reduction potential of metal ion, the higher will be its oxidizing capacity.
Since, `"E"_("MnO"_4^-//"Mn"^(2+))^⊖` has value equal to 1.51 V hence it is the strongest oxidizing agent.
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