Advertisements
Advertisements
Question
Two trees 7 m and 4 m high stand upright on a ground. If their bases (roots) are 4 m apart, then the distance between their tops is ______.
Options
3 m
5 m
4 m
11 m
Advertisements
Solution
Two trees 7 m and 4 m high stand upright on a ground. If their bases (roots) are 4 m apart, then the distance between their tops is 5 m.
Explanation:
Let BE be the smaller tree and AD be the bigger tree.
Now, we have to find AB (i.e. the distance between their tops).

By observing,
ED = BC = 4 m and BE = CD = 4 m
In ΔABC, BC = 4 m
And AC = AD – CD = (7 – 4) m = 3 m
In right angled ΔABC,
AB2 = AC2 + BC2 ...[By Pythagoras theorem]
= 42 + 32
= 16 + 9
⇒ AB2 = 25
⇒ AB = `sqrt(25)`
⇒ AB = 5 m
Therefore, the distance between their tops is 5 m.
APPEARS IN
RELATED QUESTIONS
Two towers of heights 10 m and 30 m stand on a plane ground. If the distance between their feet is 15 m, find the distance between their tops
In the given figure, ABC is a triangle in which ∠ABC < 90° and AD ⊥ BC. Prove that AC2 = AB2 + BC2 − 2BC.BD.

Identify, with reason, if the following is a Pythagorean triplet.
(11, 60, 61)
In the following figure, AD is perpendicular to BC and D divides BC in the ratio 1: 3.
Prove that : 2AC2 = 2AB2 + BC2
In the right-angled ∆LMN, ∠M = 90°. If l(LM) = 12 cm and l(LN) = 20 cm, find the length of seg MN.
The sides of the triangle are given below. Find out which one is the right-angled triangle?
8, 15, 17
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AB2 + AC2 = 2AD2 + `(1)/(2)"BC"^2`
AD is perpendicular to the side BC of an equilateral ΔABC. Prove that 4AD2 = 3AB2.
∆ABC is right-angled at C. If AC = 5 cm and BC = 12 cm. find the length of AB.
In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
