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Question
Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m, what is the distance between their tops?
Options
13 m
14 m
15 m
12.8 m
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Solution
13 m
Explanation;
Hint:
AC2 = AE2 + EC2 .....(Distance between the two tops)
= 52 + 122
= 25 + 144
= 169
AC = `sqrt(169)` = 13 cm
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*(l, m, n are opposite sides of ∠L, ∠M, ∠N respectively)
Activity: In ∆LMN, l = 5, m = 13, n = `square`
∴ l2 = `square`, m2 = 169, n2 = 144.
∴ l2 + n2 = 25 + 144 = `square`
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∴ By Converse of Pythagoras theorem, ∆LMN is right angled triangle.
