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Karnataka Board PUCPUC Science 2nd PUC Class 12

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 × 10^−22 C/m2.

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Question

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 × 10−22 C/m2. What is E:

  1. in the outer region of the first plate,
  2. in the outer region of the second plate, and
  3. between the plates?
Numerical
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Solution

Given: Charge density of plate, σ = 17.0 × 10−22 C/m2

Permittivity of free space, ε0 = 8.85 × 10−12 C N−1 m2

As both plates have the same surface charge density σ.

`E_A = E_B = σ/(2ε_0)`

(a) In region-I,

  • The field due to positive plate A is toward the left.
  • The field due to negative plate B is toward the right.

So the fields oppose each other.

EI = EB − EA 

= `σ/(2ε_0) - σ/(2ε_0)`

= 0

(b) In region-III,

  • The field due to plate A is toward the right.
  • The field due to plate B is toward the left.

Again, the fields oppose each other.

EIII = EA − EB 

= `σ/(2ε_0) - σ/(2ε_0)`

= 0

(c) In region-II,

  • The field due to the positive plate is toward the right.
  • The field due to the negative plate is also toward the right.

Hence, the fields add.

EII = EA + EB 

= `σ/(2ε_0) + σ/(2ε_0)`

= `(σ + σ)/(2ε_0)`

= `(2σ)/(2ε_0)`

= ` σ/ε_0`

= `(17.0 xx 10^-22)/(8.854 xx 10^-12)`

= 1.92 × 10−10 N/C

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Chapter 1: Electric Charge and Fields - EXERCISES [Page 44]

APPEARS IN

NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charge and Fields
EXERCISES | Q 1.23 | Page 44
NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charges and Fields
Exercise | Q 1.24 | Page 48
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