मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 × 10^−22 C/m2.

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प्रश्न

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 17.0 × 10−22 C/m2. What is E:

  1. in the outer region of the first plate,
  2. in the outer region of the second plate, and
  3. between the plates?
संख्यात्मक
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उत्तर

Given: Charge density of plate, σ = 17.0 × 10−22 C/m2

Permittivity of free space, ε0 = 8.85 × 10−12 C N−1 m2

As both plates have the same surface charge density σ.

`E_A = E_B = σ/(2ε_0)`

(a) In region-I,

  • The field due to positive plate A is toward the left.
  • The field due to negative plate B is toward the right.

So the fields oppose each other.

EI = EB − EA 

= `σ/(2ε_0) - σ/(2ε_0)`

= 0

(b) In region-III,

  • The field due to plate A is toward the right.
  • The field due to plate B is toward the left.

Again, the fields oppose each other.

EIII = EA − EB 

= `σ/(2ε_0) - σ/(2ε_0)`

= 0

(c) In region-II,

  • The field due to the positive plate is toward the right.
  • The field due to the negative plate is also toward the right.

Hence, the fields add.

EII = EA + EB 

= `σ/(2ε_0) + σ/(2ε_0)`

= `(σ + σ)/(2ε_0)`

= `(2σ)/(2ε_0)`

= ` σ/ε_0`

= `(17.0 xx 10^-22)/(8.854 xx 10^-12)`

= 1.92 × 10−10 N/C

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पाठ 1: Electric Charge and Fields - EXERCISES [पृष्ठ ४४]

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एनसीईआरटी Physics Part I and II [English] Class 12
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