Question

Two different dice are thrown together. Find the probability that the numbers obtained is a doublet of odd numbers.

Answer 1

The outcomes when two dice are thrown together are

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Total number of outcomes = 36

Let C be the event of getting a doublet of odd numbers.

The outcomes in favour of event C are (1, 1), (3, 3), (5, 5).

Number of favourable outcomes = 3

∴ `P(C) = "Number of favourable outcomes"/"Total number of outcomes" = 3/36 = 1/12`.