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Question
Two bodies A and B whose masses are in the ratio 1 : 2 are suspended from two separate massless springs of force constants kA and kB respectively. If the two bodies oscillate vertically such that their maximum velocities are in the ratio 1 : 2, the ratio of the amplitude A to that of B is
Options
`sqrt(("k"_"B")/(2"k"_"A"))`
`sqrt(("k"_"B")/(8"k"_"A"))`
`sqrt((2"k"_"B")/("k"_"A"))`
`sqrt((8"k"_"B")/("k"_"A"))`
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Solution
`sqrt(("k"_"B")/(8"k"_"A"))`
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