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Question
A simple pendulum is suspended from the roof of a school bus which moves in a horizontal direction with an acceleration a, then the time period is
Options
`"T" ∝ 1/("g"^2 + "a"^2)`
`"T" ∝ 1/sqrt("g"^2 + "a"^2)`
`"T" ∝ sqrt("g"^2 + "a"^2)`
`"T" ∝ ("g"^2 + "a"^2)`
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Solution
`"T" ∝ 1/sqrt("g"^2 + "a"^2)`
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